Up: PrntFile text
Previous: Page 3
Next: Page 5

---

KE KE1 KE2 KE3
= KE
4.725 10⁶
1.2 10⁶
3.125 10⁶
0
1.6 10⁶
1.2 10⁶
1.2 10⁶
9 10⁵
0
0
1.2 10⁶
9 10⁵
3.125 10⁶
0
3.125 10⁶
2.551 10¹⁰
0
2.551 10¹⁰
0
0
2.551 10¹⁰
4.167 10⁶
2.551 10¹⁰
4.167 10⁶
1.6 10⁶
1.2 10⁶
0
2.551 10¹⁰
1.6 10⁶
1.2 10⁶
1.2 10⁶
9 10⁵
2.551 10¹⁰
4.167 10⁶
1.2 10⁶
5.067 10⁶
Force Matrix
f
F1x
F1y
F2x
10000
F3x
0
Boundary Conditions: d1x=d1y=d2x=d3x=0
d2y
d3y . KE_, 3 3
KE_, 5 3
KE_, 3 5
KE_, 5 5
1 10000
0
= d2y
d3y
0.01351
0.01111
= . KE
0
0
0
d2y
0
d3y
1.333 10⁴
1 10⁴
6.123 10¹³
1 10⁴
1.333 10⁴
7.276 10¹²
Forces
Stress in Element 1
1x . . E
L1 ( ) cos( ) 1 sin( ) 1 cos( ) 1 sin( ) 1
0
0
0
d3y
= 1x 1.667 103

---