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Force In node 3
i .. 0 1
j .. 0 5
KF3_, i j KE , i 4 j
F3x
F3y . KF3
0
0
d2x
d2y
0
0
= F3x
F3y
5 10³
5 10³
Stress in Element 1
1x . . E
L1 ( ) cos( ) 1 sin( ) 1 cos( ) 1 sin( ) 1
0
0
d2x
d2y
= 1x 1.414 10³
Stress in Element 2
2x . . E
L1 ( ) cos( ) 2 sin( ) 2 cos( ) 2 sin( ) 2
d2x
d2y
0
0
= 2x 1.414 103

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